3a. Truncated octahedron 6/4 8/6 from truncation of cub 6/4

Data

The distance from the centre of the cube to the centre of the square is EP /2 .

The distance from the centre of the the truncated octahedron to the centre of the square(red) is EA×1.41. These two distances are equal, thus EA=EP×0.35

The distance between the mid-point of the cube square edge and the corner of the

truncated octahedron square (red) is EP/2 minus EA×Ö2/2 i.e., EP×0.15.

Construction

The six squares (red) are applied on the cube squares.The eight corners (yellow) are cut off, resulting in

eight hexagons (green-blue).

Line 1:Cube, net and solid .

Line 2: Truncated octahedron , net and solid